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21.6y^2-48y-15=0
a = 21.6; b = -48; c = -15;
Δ = b2-4ac
Δ = -482-4·21.6·(-15)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-60}{2*21.6}=\frac{-12}{43.2} =-12/43.2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+60}{2*21.6}=\frac{108}{43.2} =2+13.5/27 $
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